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논문 기본 정보

자료유형
학술저널
저자정보
저널정보
대한의생명과학회 대한의생명과학회지 대한의생명과학회지 제7권 제3호
발행연도
2001.9
수록면
99 - 102 (4page)

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초록· 키워드

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Toluene is mainly metabolized in liver by oxidative pathway. Oxigen free radicals occur through the process of toluene metabolism. Therefore it causes tissue and cell injury by the oxygen free radicals from the metabolism of toluene. Melatonin acts as a highly efficient free radical scavenger that protects cells from damage by oxygen free radicals. To test this hypothesis, toluene hepatotoxicity was induced by an abdominal injection of toluene. To see if the melatonin protects the rat's liver, melatonin was administrated orally, at the time of each toluene injection. Aspartate aminotransferase (AST), alanin aminotransferase (ALT), latic dehydrogenase (LDH) and alkaline phosphatase (ALP) levels in serum were measured to estimate hepatic function. Malondialdehyde (MDA), which gives an indirect index of oxidative injury was also measured. Hippuric acid is the last metabolic production of toluene was measured by HPLC. There were significantly higher in AST, ALT, LDH, MDA and hippuric acid in toluene group, but there were no significant difference in melatonin group except ALT and hippuric acid. There was significantly lower in ALP level in toluene group, but there was no significant difference melatonin group, suggesting a significant hepatotoxicity due to oxygen free radicals through the process of toluene metabolism. Melatonin treatment significantly protected hepatic function and free radical-mediated injury in the liver against toluene-induced changes. Accordingly, this study shows that melatonin is helpful in protecting liver injury by acute toluene intoxication.

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영어 초록
INTRODUCTION
MATERIALS AND METHODS
RESULTS
DISCUSSION
REFERENCES

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